A Proof that 0 = 1  (Can You Spot the Mistake?)

A Proof that 0 = 1 (Can You Spot the Mistake?)

A Proof that 0 = 1 (Can You Spot the Mistake?)

Tricky Elementary School Problem, Can you solve it in 20 seconds? https://www.youtube.com/watch?v=jPxfk2ioWls Please Subscribe! :) A Proof that 0 = 1. I do not know what to believe any more... except that there is obviously a mistake! :)
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Рейтинг 9.3 из 10 на основе 1016 оценок и 1016 отзывов.
patrickJMT
patrickJMT
Please subscribe while you are here! It is strange to me that Youtube is suddenly promoting this video as it was just a random 'fun video' I made a long time ago and is certainly not anything special. Most of my videos are practical tutorials that will hopefully help people pass their classes! Subscriptions are the currency of Youtube, so even if you are not a huge fan of this video, it helps me make those practical videos that everyone benefits from. Thanks so much! And... if you like this video please let me know. I have tons of 'puzzle' problems that I can post!
Iceman ___
Iceman ___
You don't have to. You do √(-1/2)(-1/2)
Morad Morad
Morad Morad
nice try
Girl More
Girl More
ok that's also a 6...
Mehraj Chhetri
Mehraj Chhetri
whenever we remove square root we have to remember that we will get 2 values simultaneously one positive value and one negetive value... x=√1 means x=+1 or x=-1 in the above problem (4-9/2)²=(5-9/2)² (4-9/2)=√(5-9/2)² 4-9/2=-(5-9/2) or 4-9/2=5-9/2 4=4 or 4=5 but 4 !=9 so 4=4 is correct even 4-9/2=-1/2 and 5-9/2=1/2 that means (4-9/2)=-(5-9/2) when we open roots we will get two values one is positive something and one is negetive something
Black Widower XIX
Black Widower XIX
Lol dude sq root (x^2) = |x|
Discover The World
Discover The World
Here is the mistake (4-9/2)^2 = (5-9/2)^2 must be |4-9/2|=|5-9/2|
Exterminator9000
Exterminator9000
If a=b, and b=c, that does not necessarily mean a=c... Here's what I mean: A=5 B=sqrt25 C=-5 In that case, (where sqrt = square root of), A=/=C, since the properties of exponents and square roots are a bit different than those of usual addition, subtraction, multiplication, and division.
Noone At all
Noone At all
a=4-9/2= -1/2 b=5-9/2=1/2 Yes a^2=b^2 (they are both 1/4). But a != b. a^2=b^2 concludes that a=b OR a= - b, not that a=b
MlgEpicBanana69
MlgEpicBanana69
how the heck is 4-9/2 = *5*-9/2 its one number more. :P
Jordan
Jordan
Step 8 is incorrect
Pi
Pi
If you squareroot, or in general ^(1/2n) n being a natural number, you need to use the absolute value. So (4-9/2)² = (5-9/2)² becomes |4-9/2| = |5-9/2| and if you compute this it gets 0.5 = 0.5. :P We can say we end up with 2 solutions: ±(4-9/2) = ∓(5-9/2)
Miloš Lošmi
Miloš Lošmi
U cant root both side
brett knoss
brett knoss
My daddy taught me that 0 x 0 =Fag! Daddy drank.
Bogdan Colesiu
Bogdan Colesiu
You can't square root like that.
Mahesh Reddy
Mahesh Reddy
u r rong
john johnson
john johnson
The step where you have square the factors will have to be invalid(they become positive), because that would mean that -20=20.
ConnorConnor
ConnorConnor
0:51 didja know that 6² = 36 aswell?
vineet nair
vineet nair
the square thing u did after factorising was wrong. (a-b)*2 is (a+b)(a-b) not (a-b)(a-b)
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close but (4-9/2)" "2 = (5-9/2)'' '' 2 does not mean 4-9/2= 5-9/2
Lusti Tilk
Lusti Tilk
boring'
Zion J
Zion J
It took me 3 years to find the mistake (I watched the video every six months), but I FINALLY found it! It's the step in which you take the square root of both sides. Just because x^2 = y^2 does not mean that x = y (although both x and y need to equal something wild; in the video they certainly do).
Derek Xiong
Derek Xiong
Just the magic about squared
Nikita Nopants
Nikita Nopants
Where did 9 over 2 come from? If you want to write the number 9 as a fraction it's 9 over 1.
thomi dhia
thomi dhia
i dont know if it can be factored
Dzenis Abdukic
Dzenis Abdukic
am I the only one who realizes that he forgot brackets in the 4th line... or am I just stupit
Rendy Setiawan
Rendy Setiawan
1st statement is true -20 = -20 2nd statement is true 16 - 36 = 25-45 -20 = -20 3rd statement is true 4^2 - 4.9 = 5^2 - 5.9 16 - 36 = 25-45 -20 = -20 4th statement is the beginning of disaster ... 4^2 - 4.9 + 81/4 = 5^2 - 5.9 + 81/4 4^2 - 4.9 = 5^2 - 5.9 16 - 36 = 25-45 -20 = -20 But, if we calculate directly 4^2 - 4.9 + 81/4 = 1/4 and also 5^2 - 5.9 + 81/4 = 1/4 Contradiction, right ? Why ? Since we try to force the 4th statement is equivalent with 3rd statement, so we can prrof this wrong with a simple logic, here we go : In general ways, Let a,b,c,d are Real numbers and assume a - b = c - d (true), s.t (a - b = c - d) \u003c---\u003e (a - b + e = c - d + e) ---\u003e [(a - b) = a - b + e ] and [(c -d) = c - d + e] IS WRONG Proof : a - b = c - d ---\u003e a- b + e = c - d + e (TRUE ---\u003e TRUE : TRUE) a- b + e = c - d + e ---\u003e a - b = c -d (TRUE ----\u003e TRUE : TRUE) so, a - b = c - d \u003c---\u003e a- b + e = c - d + e (ALSO TRUE) [(a - b) = a - b + e ] (FALSE) [(c -d) = c - d + e] (FALSE) so, [(a - b) = a - b + e ] and [(c -d) = c - d + e] (ALSO FALSE) Therefore, (a - b = c - d) \u003c---\u003e (a - b + e = c - d + e) ---\u003e [(a - b) = a - b + e ] and [(c -d) = c - d + e] (TRUE \u003c----\u003e TRUE) --\u003e (False and False) TRUE ---\u003e False False In case, we can briefly prove this : 4^2 - 4.9 = 5^2 - 5.9 \u003c---\u003e [4^2 - 4.9 + 81/4 = 5^2 - 5.9 + 81/4] ---\u003e [4^2 - 4.9 = 4^2 - 4.9 + 81/4] AND [5^2 - 5.9 =5^2 - 5.9 + 81/4 ] [-20 = -20 \u003c---\u003e 1/4 = 1/4] ---\u003e [-20 = 1/4] AND [-20 = 1/4] [TRUE \u003c----\u003e TRUE] ---\u003e [FALSE] AND [FALSE] TRUE ---\u003e [FALSE] FALSE... DISASTER OF LOGIC THINKING
ronit mann
ronit mann
The answer is completely simple guys See -20=-20 Later he adds 81/4=20 If we see this as 0=0 Then 0*1=0*2 1=2 That's how it is
MC cashMax
MC cashMax
The equation on the seventh row from the top, if you remove the exponent and do the math you will have a positive number on one side and negivitve on the other side of the equation but the absolute value of both numbers are equal, making the equation false. I believe you wrongly factored the fith row because the fith row is correct, however you disguised the mistake by exploiting the root problem. The problem being, the square root of every number is both the square root of the number and the square root of the number as a negative number.Example: Btw 25^(1/2) is another means of describing the square root of 25, I just didn't have a root symbol 25^(1/2) = 525^(1/2) = (-5) -5 x -5 = 255 x 5 = 25
Chandan Yogesh
Chandan Yogesh
the mistake was that u added 81
Priyank Oza
Priyank Oza
x^2=y^2 does not implies that x=y // we can also have x=-y!! which is so in our case
halim taouilt
halim taouilt
(4-4.5)^0.5 faux écriture
فائز زائف
فائز زائف
hhhhhhhhhhhhh 2*4*9/2 and 2*5*9/2
Andy Dong
Andy Dong
Kinda expected something more interesting than that
Gabriel Pawłowski
Gabriel Pawłowski
well this is not a proof
Laila Alalmaniya
Laila Alalmaniya
you had to solve the binomic formulas, not just delete the "square"
Som Nath
Som Nath
We can write-20=-20*1 then 1 equals - 20/-20 which is little simple
sundar pal
sundar pal
X squre =y squre does not mean x = y
Hoozi Tomas
Hoozi Tomas
everything's ok until you assassinated maths with your way of solving an equasion of sort a^2=b^2
Navjot Allachauria
Navjot Allachauria
7th step is wrong step. You can't neglect the negative values whenever u take the sqrt. (4-9/2)^2=(5-9/2)^2 (4-9/2)=+ or -(5-9/2) in this case (4-9/2)=-(5-9/2) 4-9/2=-5+9/2 9=9.
lingqi Wen
lingqi Wen
The problem is on the completing the square between 2:25 to 2:49
Andrew Qi
Andrew Qi
I think (I don't know) 4 -(9/2)^2 is not equal to 5-(9/2)^2.
Anthony Kioupidis
Anthony Kioupidis
The mistake has done when you erased the squares: (4-9/2 )^2= (5-9/2)^2 =\u003e [ (8-9)/2]^2 = [(10-9)/2]^2 =\u003e ( 8-9)^2 = (10-9)^2 =\u003e (-1)^2 = 1^2 =\u003e 1=1
David Masabo
David Masabo
first mistake is that u didn't group 4×9 and 5×9 so by system of operations the equation is wrong. finally, just because 1^2=-1^2 doesn't mean that 1=-1. example x^2=y^2 then x doesn't have to be equal to y. x^2=y^2, x^2=-y^2 so in this case y can actually have 2 values and so can x so right answer should be x^2=+-y^2
Aniket Ghosh
Aniket Ghosh
How is the square of a number negative?
Aniket Ghosh
Aniket Ghosh
Shouldn't the square root of these numbers be a lateral number?
Dominic Cingoranelli
Dominic Cingoranelli
Not to mention the issue of the squares, if you assume the sides are equal then of course it'll work. The thing with proofs, is you are changing one side (With clever forms of one, etc.) so that you get the other side.
X Magistrty X
X Magistrty X
Its easy n^2 = (-n)^2 But square rooting both side give us n = -n thats why it gives us 0 = 1 if you just solve without square rooting it gives..... (1/2)^2 = (-1/2)^2 L.H.S = R.H.S Hence proved
Siddharth Rodrigues
Siddharth Rodrigues
you can't cancel the squares on both sides well in first look u got me
Franz
Franz
you can't square root both sides like that, if you evaluate (4-9/2)^2 and (5-9/2)^2 they both equal to a quarter.
Connor Sponsler
Connor Sponsler
The 6th step has no basis is any real mathematics.
Giovanni Violo
Giovanni Violo
ha sbagliato a "comporre" il quadrato di binomio di (4-9/2) e quindi di (5-9/2)
Μαρία Μουστοπούλου
Μαρία Μουστοπούλου
ΠΟΎ ΕΊΝΑΙ ΤΟ ΑΠΌΛΥΤΟ ΡΕ ΓΕΛΟΊΕ ????
Rohan Albal
Rohan Albal
the real answer? you cant divide by zero !